Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
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Sample-mean variance and positive semidefinite sample ACVF

Statement

Let X=(Xt)t∈Z be weakly stationary, with mean μ and autocovariance γ, and define Xˉn:=n−1∑t=1nXt for n≥1. Then Var⁡(Xˉn)=1n2∑∣h∣<n(n−∣h∣)γ(h). If ∑h∈Z∣γ(h)∣<∞, then 0≤Var⁡(Xˉn)≤1n∑h∈Z∣γ(h)∣, so E[(Xˉn−μ)2]→0: the sample mean is consistent in L2. No mixing property or central limit theorem is asserted here. For every finite real data vector, the zero-extended biased sample ACVF γ^n of Autocovariance and sample autocovariance has nonnegative Toeplitz quadratic forms.

Facts & Assumptions

Given: A weakly stationary real process X=(Xt)t∈Z with mean μ and autocovariance γ, an integer n≥1, and (for the consistency conclusion) ∑h∈Z∣γ(h)∣<∞. The sample ACVF conclusion applies to every finite real data vector of length n.

[F1]

Strict and weak stationarity for integer-indexed time series: each Xt has finite second moment, E[Xt]=μ is constant, and γ(h)=Cov⁡(Xt+h,Xt) is independent of t.

[F2]

Moments, variance, and covariance on a probability space defines variance and covariance from centered squares and products; Variance and covariance identities for random variables gives covariance bilinearity on finite linear combinations.

[F3]

Linearity, monotonicity, and the modulus bound for expectation: expectation is linear on integrable random variables.

[F4]

Autocovariance and sample autocovariance: after centering a data vector by its sample mean, γ^n(h) is the 1/n lagged product sum, with zero extension for ∣h∣≥n.

Proof

Proof technique: count pairs by their lag, bound the resulting covariance sum, and write the sample Toeplitz form as a sum of squares.

1.1F1F2F3givenalgebra

Each Xt is integrable because 2∣Xt∣≤1+Xt2 and the probability space has total mass one. Repeated application of [F3] gives E[Xˉn]=μ. By [F2] and its cited covariance-bilinearity supplier, Var⁡(Xˉn)=n−2∑s=1n∑t=1nCov⁡(Xs,Xt).

1.2F4givenalgebra

Fix a data vector x1,…,xn, let yt=xt−xˉn for 1≤t≤n, and set yt=0 otherwise. By [F4], for every h∈Z, γ^n(h)=n−1∑t∈Zytyt+h. The sum is finite because y has finite support. Replacing t by t−h and commuting the real factors shows γ^n(−h)=γ^n(h).

2.1F1step 1.1algebra

For s,t∈{1,…,n}, [F1] gives Cov⁡(Xs,Xt)=γ(s−t). For each integer h with ∣h∣<n, exactly n−∣h∣ ordered pairs (s,t) satisfy s−t=h, and no ordered pair has ∣s−t∣≥n. Grouping the finite sum in step 1.1 by h=s−t proves the variance identity.

3.1step 2.1givenalgebra

Under absolute covariance summability, every weight n−∣h∣ in the identity is between 0 and n, so 0≤Var⁡(Xˉn)≤n−2∑∣h∣<n(n−∣h∣)∣γ(h)∣≤n−1∑h∈Z∣γ(h)∣.

4.1step 1.1step 3.1algebra

Step 1.1 gives E[Xˉn]=μ. Therefore E[(Xˉn−μ)2]=Var⁡(Xˉn), and the bound in step 3.1 tends to zero as n→∞. This is precisely L2 consistency for the mean.

5.1step 1.2givenalgebra∎

Let (aj)j∈J be any finitely supported real coefficient family indexed by integers. Expanding the finite sums and using the evenness from step 1.2 gives ∑j,k∈Jajakγ^n(j−k)=n−1∑u∈Z(∑j∈Jajyu+j)2≥0. Only finitely many terms on the right are nonzero, and every summand is a square. Thus every finite Toeplitz quadratic form of γ^n is nonnegative.

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