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Ordinary importance sampling has finite variance and a CLT under a weighted second moment

Statement

Use the hypotheses and notation of Ordinary importance sampling is unbiased. Define Yi:={f(Xi)p~(Xi)/(Zpq(Xi)),q(Xi)>0,0,q(Xi)=0,θ:=∫f dπ,σ2:=Var⁡Q(Y1). If EQ[Y12]<∞, then μ^IS has finite variance and Var⁡Q(μ^IS)=σ2n=1n(1Zp2∫{q>0}f(x)2p~(x)2q(x) dμ(x)−θ2). This finite-sample conclusion is choice-free. For the central limit conclusion, let (Xi)i≥1 be an IID sequence with law Q, and apply the estimator to its first n draws for each n≥1. If, in addition, AC holds, then n(μ^IS−θ)⇒N(0,σ2). No finite variance or normal-limit claim is made when the weighted second moment is infinite.

Facts & Assumptions

Given: The integrable ordinary importance sampling setup from Ordinary importance sampling is unbiased, plus EQ[Y12]<∞. For the CLT conclusion, take an IID sequence (Xi)i≥1 with law Q and assume AC.

[F1]

Ordinary importance sampling: The estimate is the sample average of the weighted values Yi=f(Xi)p~(Xi)/(Zpq(Xi)), with value 0 when q(Xi)=0; the algorithm also establishes that this piecewise weighted-integrand map is measurable.

[F2]

Ordinary importance sampling is unbiased: Under its support and integrability hypotheses, EQ[μ^IS]=θ=∫f dπ.

[F3]

Measurable coordinatewise functions preserve independence: Applying measurable coordinatewise maps to an independent family preserves independence.

[F4]

Identical distribution and IID families: IID means a common law and mutual independence.

[F5]

Variance adds for every finite pairwise-independent family: The variance of a finite sum of pairwise-independent square-integrable real variables is the sum of their variances. Variance and covariance identities for random variables: Covariance is bilinear on finite linear combinations, so Var⁡(aY)=a2Var⁡(Y) and Var⁡(Y)=E[Y2]−(EY)2.

[F6]

Change of variables for expectation: For a nonnegative measurable function of a random element with law Q, expectation equals its integral against Q.

[F7]

Moments, variance, and covariance on a probability space: For square-integrable real Y, Var⁡(Y)=E[(Y−EY)2].

[F8]

Lindeberg–Lévy limit for the IID Monte Carlo mean: Under AC, a real IID sample with positive finite variance satisfies n(Yˉn−EY1)⇒N(0,Var⁡(Y1)).

[F9]

A nonnegative measurable function has integral 0 exactly when it vanishes almost everywhere: A nonnegative measurable function has integral zero exactly when it vanishes almost everywhere.

[F10]

Standard normal and normal laws: N(m,0) is the Dirac law δm.

[A1]

The Axiom of Choice: AC asserts that every family of nonempty sets has a choice function; it is assumed only for the central limit conclusion.

[F11]

Integrating against a density agrees with integrating the product: for a nonnegative measurable density r and nonnegative measurable h, ∫h d(r dμ)=∫hr dμ, including infinite values.

Proof

Given: The weighted values Yi from the Statement and the finite second moment EQ[Y12]<∞.

1.1F1F3F4given

By [F1], each Yi is obtained from Xi by the same measurable weighted-integrand map and μ^IS=n−1∑i=1nYi. Since the Xi are IID, [F3] preserves independence and their common law under this map; [F4] therefore makes (Yi) IID.

2.1F2F5givenstep 1.1algebra

Applying [F2] to a sample of size one gives EQY1=θ, and it also gives EQ[μ^IS]=θ for the supplied sample. By step 1.1 every Yi has the same finite second moment and variance σ2, and the finite family is pairwise independent. Thus [F5] gives Var⁡Q(∑i=1nYi)=nσ2 and Var⁡Q(μ^IS)=n−2(nσ2)=σ2/n.

3.1F1F5F6step 2.1givenalgebraF11

Use [F11] with density r=q for integration against Q. Applying [F6] to the nonnegative squared weighted integrand gives EQ[Y12]=Zp−2∫{q>0}f(x)2p~(x)2/q(x) dμ(x). By [F5] and step 2.1, σ2=EQ[Y12]−θ2, proving the displayed variance formula.

4.1A1F7F8F9F10step 1.1step 2.1step 3.1givenalgebra∎

For the CLT, use the given IID sequence (Xi)i≥1 and assume AC as in [A1]. The measurable transformation in step 1.1 now makes (Yi)i≥1 IID. If σ2>0, [F8] applies to the IID sequence from step 1.1 with mean θ from step 2.1 and yields the stated normal limit. If σ2=0, [F7] gives EQ[(Y1−θ)2]=0, so [F9] implies Y1=θ Q-almost surely. By the common-law conclusion of step 1.1, each event {Yi≠θ} is null; for each fixed n, the union of the first n such events is null. Thus Yˉn=θ almost surely for each n, and the centered sample mean has law δ0=N(0,0) for every n by [F10]. The variance argument in the preceding steps used no choice axiom.

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