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An AR(1) covariance forecast and general-RHS Toeplitz solve

Statement

Assume a real, mean-zero, weakly stationary process Xt satisfies the causal AR(1) model Xt=12Xt−1+εt in L2, where εt is centered with variance 3/4, is uncorrelated with Xs for every s<t, and the process is weakly stationary. Here “AR(1)” means precisely this first-order autoregression; the stated uncorrelatedness is the innovation orthogonality used below. Then its autocovariance function (ACVF) is γ(h)=2−∣h∣. The order-two Durbin–Levinson output is ϕ2=(1/2,0)T and ν2=3/4. Separately, for T=(11/21/21) and b=(1,1)T, the general-RHS Hermitian Toeplitz solver returns T−1b=(2/3,2/3)T by the Gohberg–Semencul formula.

Facts & Assumptions

Given: The process and innovation hypotheses in the Statement, the Durbin–Levinson covariance-input procedure, and the exact Hermitian Toeplitz solver.

[F1]

Weak stationarity supplies a constant mean and an ACVF γ(h)=Cov⁡(Xt+h,Xt) depending only on lag. Strict and weak stationarity for integer-indexed time series Autocovariance and sample autocovariance

[F2]

Covariance is symmetric and bilinear for finite linear combinations of square-integrable variables. Moments, variance, and covariance on a probability space Variance and covariance identities for random variables

[F3]

The real Durbin–Levinson recursion computes ϕk,νk from γ(0),…,γ(k) when the leading covariance blocks are positive definite. Durbin–Levinson forecast recursion

[F4]

Under those leading-block hypotheses, ϕk solves the prediction equations and νk=γ(0)−rkTϕk. Durbin–Levinson solves the successive prediction equations

[F5]

The Hermitian Toeplitz solver constructs the endpoint inverse columns and applies the exact Gohberg–Semencul formula. General-RHS Hermitian Toeplitz solve by reflection recursion and Gohberg–Semencul The Hermitian positive-definite Gohberg–Semencul formula is exact and quadratic

Proof

1.1givenF1F2algebra

Centering and weak stationarity give E[Xt]=0 and γ(0)=Var⁡(Xt) for every t. From the autoregression and innovation orthogonality, γ(0)=Var⁡(12Xt−1+εt)=14γ(0)+34, so γ(0)=1.

1.2givenF5algebra

For the separate general-RHS solve, set T=(11/21/21) as in the Statement. For each nonzero z∈C2, z∗Tz=∣z1+z2/2∣2+3∣z2∣2/4>0, so T is Hermitian positive definite. Its first lag data are t0=1,t1=1/2, hence α1=t1/t0=1/2, ϕ1=α1=1/2, and ν1=t0(1−∣α1∣2)=3/4. The endpoint columns from [F5] are v=(−2/3,4/3)T,u=J2v=(4/3,−2/3)T,u0=4/3>0. The lower triangular Toeplitz products are L(u)L(u)∗=(16/9−8/9−8/920/9),L(Z2v)L(Z2v)∗=(0004/9). Therefore the formula in [F5] gives T−1=(4/3−2/3−2/34/3),T−1b=(2/3,2/3)T. Direct multiplication also verifies T(2/3,2/3)T=(1,1)T.

2.1givenF1F2step 1.1induction

For each integer h≥1, covariance bilinearity and Cov⁡(εt,Xt−h)=0 give γ(h)=Cov⁡(Xt,Xt−h)=12γ(h−1). Induction yields γ(h)=2−h for h≥0; covariance symmetry gives γ(−h)=γ(h).

3.1givenF3F4step 1.1step 1.2step 2.1algebra

The order-one recursion gives κ1=γ(1)/γ(0)=1/2, ϕ1=(1/2) and ν1=1(1−1/4)=3/4. At order two, κ2=γ(2)−ϕ1,1γ(1)ν1=1/4−(1/2)(1/2)3/4=0, so ϕ2=(ϕ1,1−κ2ϕ1,1,κ2)T=(1/2,0)T and ν2=ν1(1−κ22)=3/4. By steps 1.1 and 2.1, Γ1=[1] and Γ2=T. Step 1.2 proves T Hermitian positive definite, so the real leading covariance blocks are positive definite; [F3] applies and [F4] identifies this vector as the unique prediction solution.

4.1step 3.1step 1.2algebra∎

The first calculation reuses the published real covariance prediction recursion, while the second is a distinct arbitrary-right-hand-side Hermitian Toeplitz solve; the computed vector satisfies its stated system.

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