Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-31
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For a diagonalizable matrix, the GMRES residual bound carries the eigenvector-conditioning factor κ(V)

Statement

Assume A=VΛV−1 is diagonalizable, with Λ=diag⁡(λ1,…,λn). If rm is the mth GMRES residual, then

∥rm∥2≤κ2(V)min⁡deg⁡p≤mp(0)=1max⁡1≤i≤n∣p(λi)∣ ∥r0∥2,

where κ2(V)=∥V∥2∥V−1∥2.

Facts & Assumptions

Given: A diagonalization A=VΛV−1 and an mth GMRES residual rm.

[L1]

One has rm=pm(A)r0 for some polynomial pm with deg⁡pm≤m and pm(0)=1, and GMRES chooses such a polynomial minimizing the residual norm (The GMRES residual has the form rm=pm(A)r0 with pm(0)=1 and deg⁡pm≤m).

Proof

technique · direct
1.1L1algebra

By [L1], rm=pm(A)r0=Vpm(Λ)V−1r0. Hence ∥rm∥2≤∥V∥2 ∥pm(Λ)∥2 ∥V−1∥2 ∥r0∥2. Since pm(Λ) is diagonal, its operator norm is max⁡i∣pm(λi)∣. Therefore ∥rm∥2≤κ2(V)max⁡i∣pm(λi)∣ ∥r0∥2.

2.1L1step 1.1∎

The polynomial pm from [L1] minimizes ∥p(A)r0∥2 over all polynomials with deg⁡p≤m and p(0)=1, so the bound from step 1.1 also holds after taking the minimum over that admissible class.

Depends on

Used by

Dependency tree · two levels

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Sources