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PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Posterior-mean plug-in measurement scores need not be exact

Statement

Let X0 take values −1 and 1 with equal probability, let Xσ=X0+σZ with σ>0 and standard Gaussian noise independent of X0, and let Y=X0+τW for W∼N(0,1) independent of (X0,Z), with τ>0. At the observation y=0, the exact measurement density rσ(0∣x)=E[φτ(−X0)∣Xσ=x] is constant in x, so its score is zero. The exact posterior mean is mσ(x)=E[X0∣Xσ=x]=tanh⁡(x/σ2), where tanh⁡(t)=(e2t−1)/(e2t+1). The plug-in density φτ(−mσ(x)) has score −mσ(x)mσ′(x)/τ2, which is nonzero for x≠0. Thus evaluating the measurement likelihood at the exact posterior mean does not in general recover the exact measurement score; this example does not rule out equality in special models.

Facts & Assumptions

Given: The two-point prior, the independent Gaussian noising and observation noises, and σ,τ>0.

[A1]

P(X0=1)=P(X0=−1)=1/2 and Xσ=X0+σZ with Z standard Gaussian independent of X0.

[A2]

The observation noise W∼N(0,1) is independent of (X0,Z), and Y=X0+τW.

[A3]

The Gaussian density is φτ(v)=(2πτ)−1exp⁡(−v2/(2τ2)).

[F1]

Under additive Gaussian noising, the posterior mean is mσ(x)=x+σ2∇log⁡pσ(x). Conditional-score and Tweedie identities for Gaussian smoothing

[F2]

The exact measurement score is gσ(x,y)=∂xlog⁡rσ(y∣x), where rσ(y∣x) averages the clean-state likelihood over the conditional law of X0 given Xσ=x. Diffusion prior and measurement scores

Proof

Given: The hypotheses in the Statement.

1.1A1F1algebra

For x∈R, Bayes' formula gives P(X0=1∣Xσ=x)P(X0=−1∣Xσ=x)=φσ(x−1)φσ(x+1)=exp⁡(2x/σ2). Therefore the posterior mean is (e2x/σ2−1)/(e2x/σ2+1)=tanh⁡(x/σ2), agreeing with the conditional-mean version in [F1].

1.2A1A2A3F2algebra

At y=0, both possible clean states have the same likelihood density: φτ(0−1)=φτ(0+1)=φτ(1). Averaging these equal values over the conditional law from [F2] gives rσ(0∣x)=φτ(1) for every x, so its logarithmic derivative and the exact measurement score are zero.

2.1A3step 1.1algebra

The plug-in log density is log⁡φτ(−mσ(x))=−log⁡(2πτ)−mσ(x)2/(2τ2). Differentiating the quotient expression in step 1.1 gives mσ′(x)=4e2x/σ2/(σ2(e2x/σ2+1)2)>0. Hence the plug-in score is −mσ(x)mσ′(x)/τ2, which is nonzero whenever x≠0.

3.1step 1.2step 2.1given∎

The exact score in step 1.2 and the plug-in score in step 2.1 disagree for every nonzero x. Thus the exact posterior mean does not, in general, make likelihood-at-the-mean guidance equal to the exact measurement score. The calculation permits special cases of equality but refutes a general identity.

Depends on

Used by

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