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PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
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The isotropy action on G/H is induced by Ad modulo h

Statement

Assume ACω. Let H≤G be closed. For h∈H, the differential at eH of the isotropy diffeomorphism LhG/H corresponds, under g/h≅TeH(G/H), to

X+h⟼Ad⁡hX+h.

Facts & Assumptions

Given: ACω, a closed subgroup H≤G, and h∈H.

[A1]

The map dqe identifies g/h with TeH(G/H). The Axiom of Countable Choice (ACω), Tangent space of a homogeneous quotient.

[F1]

Ad⁡h=d(Ch)e, where Ch(g)=hgh−1. Conjugation and the adjoint representation of a Lie group.

Proof

technique · differentiate an equivariant identity
1.1F1givenalgebra

Conjugation by h maps H to itself, because h∈H. Therefore its differential preserves h=TeH, and [F1] shows that Ad⁡h descends to the stated linear map on g/h.

1.2F1algebra

For every g∈G, q(Ch(g))=hgh−1H=hgH=LhG/H(q(g)), since h−1H=H. Differentiate q∘Ch=LhG/H∘q at e to obtain dqe∘Ad⁡h=d(LhG/H)eH∘dqe.

2.1A1step 1.1step 1.2∎

Since dqe is surjective and its induced map from g/h is an isomorphism by [A1], step 1.2 says exactly that the isotropy differential is conjugate to the descended adjoint map. For h=e both are the identity; no normality of H is required. Choice is inherited only through [A1].

Depends on

Used by

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Sources