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PropositionStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Every outer-null set is Carathéodory measurable

Statement

Every set of outer measure zero, and every subset of it, is Carathéodory measurable and has outer measure zero.

Facts & Assumptions

Given: An outer measure μ on X, a set NX with μ(N)=0, and a subset SN.

[F1]

An outer measure on a set X is a function μ:P(X)[0,+] that vanishes at the empty set, is monotone, and is countably subadditive. (Outer measures)

[L1]

For every outer measure μ and all A,EX, μ(A)μ(AE)+μ(AE). (In the Carathéodory identity, the subadditive inequality is automatic)

Proof

technique · direct
1.1

Monotonicity gives 0μ(S)μ(N)=0, so μ(S)=0; for every test set A, the same argument gives μ(AS)=0.

F1algebra
2.1

Since ASA, monotonicity gives μ(A)μ(AS)=μ(AS)+μ(AS) by step 1.1; [L1] supplies the reverse inequality, so S is Carathéodory measurable.

step 1.1L1algebra

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources