Alphabeta Math
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FETI-DP is the exact dual Schur system

Statement

Let f∈W^′ and set f~=E0Tf. The constrained minimization problem

min⁡w∈W~, Bw=0(12⟨S~w,w⟩−⟨f~,w⟩)

has the saddle equations S~w+BTλ=f~, Bw=0. Eliminating w gives the FETI-DP dual system

BS~−1BTλ=BS~−1E0Tf.

On Λ=range⁡B its matrix is positive definite, and the exact multiplier solution reconstructs the unique assembled interface solution w∈W^.

Facts & Assumptions

Given: S~ is positive definite on W~, B:W~→Λ is onto with ker⁡B=W^, and E0 is the projection used by BDDC.

[F1]

FETI-DP dual system and preconditioner: F=BS~−1BT and the multiplier space is Λ=range⁡B.

[F2]

Primal interface spaces and jump convention: ker⁡B=W^ and redundant multiplier rows are represented by their range.

[F3]

Primal constraints remove local floating kernels: all subdomain vertices primal and a nonempty global Dirichlet boundary suffice for positive definiteness of S~. Here positive definiteness is an explicit hypothesis, also for other primal choices.

Proof

1.1givenF1F2algebra

The Lagrangian is L(w,λ)=12⟨S~w,w⟩−⟨E0Tf,w⟩+⟨λ,Bw⟩. Its derivative in arbitrary z∈W~ is ⟨S~w+BTλ−E0Tf,z⟩, and its multiplier derivative is Bw. Setting both derivatives to zero gives the displayed saddle equations.

2.1givenstep 1.1algebra

By the assumed positive definiteness of S~, the first equation has the unique solution w=S~−1(E0Tf−BTλ). Substitution into Bw=0 gives the displayed dual system.

3.1F1F2F3step 2.1algebra∎

If λ∈Λ and BTλ=0, write λ=Bv using [F2]. Then ⟨λ,λ⟩=⟨Bv,λ⟩=⟨v,BTλ⟩=0, hence λ=0. Thus BT is injective on Λ, and ⟨Fλ,λ⟩=⟨S~−1BTλ,BTλ⟩>0 for every nonzero λ. The exact solution satisfies Bw=0, so by [F2] it lies in W^ and solves the assembled variational problem.

Depends on

Used by

Nothing in the library uses this result yet.

Cited to discharge well-definedness by FETI-DP dual system and preconditioner.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources