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Complementary primal and dual projections share nonunit spectrum

Statement

Let V,U1,U2 be finite-dimensional real vector spaces, let A:V→V′ be symmetric positive definite, and let Li:V→Ui, Ti:Ui→V satisfy LiTi=IUi for i=1,2 and T1L1+T2L2=IV. Then the operators

G1=(L1A−1L1T)(T1TAT1),G2=(T2TAT2)(L2A−1L2T)

have the same eigenvalues, with the same multiplicities, except possibly at the eigenvalue 1.

Facts & Assumptions

Given: Finite-dimensional spaces, A symmetric positive definite, and the four displayed left-inverse and complementary-projection identities.

Proof

1.1givenalgebra

The products G1 and G2 act on U1 and U2′, respectively. Set X=L1A−1L2T:U2′→U1 and Y=T2TAT1:U1→U2′. By the given hypotheses, L1T1=I, L2T2=I, and T1L1+T2L2=I. Expanding the products gives G1−I=−XY and G2−I=−YX. In detail, G1−I=L1A−1((T1L1)T−I)AT1=−L1A−1L2TT2TAT1; also YX=T2TA(I−T2L2)A−1L2T=I−G2.

2.1givenstep 1.1algebra

If u∈U1 satisfies G1u=λu with λ≠1, then XYu=(1−λ)u, so Yu≠0. The identity G2−I=−YX gives (G2−I)Yu=−YXYu=(λ−1)Yu, hence G2(Yu)=λYu. For v∈U2′, the reverse map is v↦−Xv/(λ−1); the same identities show it is the inverse on the λ-eigenspaces. Thus these eigenspaces are isomorphic.

3.1givenstep 2.1algebra∎

Choose bases of the finite-dimensional spaces and their dual bases. Both operators are diagonalizable: T1TAT1 and L1A−1L1T are positive definite, so, writing D1=T1TAT1, G1 is similar to the symmetric positive definite product D11/2(L1A−1L1T)D11/2; likewise G2 is similar to D21/2(L2A−1L2T)D21/2, where D2=T2TAT2. The left-inverse identities make Ti injective and Li surjective, proving each factor is positive definite. Therefore equal eigenspace dimensions from step 2.1 give equal algebraic multiplicities for every λ≠1.

Remarks

Coefficient-scaled averaging and BDDC: for BDDC, L1=E0, T1=R, and E0R=IW^.

FETI-DP dual system and preconditioner: for FETI-DP, L2=B, T2=BDT, BBDT=IΛ, and BDTB+RE0=IW~.

Depends on

Used by

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Sources