Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedprecheck passverified 2026-09-24 (gpt-6-sol)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Sections of Hom are the same as smooth fibrewise linear maps

Statement

For smooth vector bundles E,F→M, smooth sections of Hom⁡(E,F) are in natural bijection with smooth vector bundle maps E→F over id⁡M.

Facts & Assumptions

Given: Smooth vector bundles E,F→M.

[L1]

In local frames, a smooth bundle map over the identity is equivalent to a smooth matrix of coefficients (Smoothness of a bundle map is equivalent to smooth local matrices).

[L2]

The Hom bundle is built from the same local matrices (Dual and Hom transition functions define smooth bundles).

Proof

technique · direct
1.1L1L2givenconstruct

A section s:M→Hom⁡(E,F) assigns to each p∈M a linear map s(p):Ep→Fp. Define Φs:E→F by Φs(v)=s(π(v))(v). In a pair of local frames, the matrix entries of s are exactly the matrix entries of Φs.

2.1L1L2step 1.1algebra∎

Conversely, a bundle map Φ:E→F over id⁡M gives a section sΦ(p)=Φ∣Ep∈Hom⁡(Ep,Fp). The constructions are inverse to one another, and [L1] together with [L2] shows that smoothness on either side is the same local matrix condition.

Depends on

Used by

Dependency tree · two levels

21 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources