Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-31
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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Bundle maps over f are sections of the pulled-back Hom bundle

Statement

Let Φ:EF be a smooth vector bundle map over a smooth map f:MN. Then Φ is naturally equivalent to a smooth section of the pulled-back Hom bundle Hom(E,fF)M.

Facts & Assumptions

Given: Smooth vector bundles EM, FN, a smooth map f:MN, and a bundle map Φ:EF over f.

[L1]

The pullback fibre product fF is a smooth vector bundle over M (The pullback fibre product is a smooth vector bundle).

[L2]

Sections of a Hom bundle are the same as fibrewise linear bundle maps over the identity (Sections of Hom are the same as smooth fibrewise linear maps).

Proof

technique · direct
1.1

For each pM, the fibre map Φp:EpFf(p) may be viewed as a linear map Ep(fF)p because (fF)p is canonically Ff(p). Hence pΦp defines a section of Hom(E,fF)M.

L1givenconstruct
2.1

In local trivializations the matrix of this section is exactly the local matrix of Φ, so the section is smooth exactly when Φ is smooth. Therefore [L2] applied to the bundles E and fF yields the required bijection.

L1L2step 1.1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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Sources