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TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-31
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The pullback fibre product is a smooth vector bundle

Statement

If π:EM is a smooth rank-r vector bundle and f:NM is smooth, then the fibre product fE is a smooth rank-r vector bundle over N.

Facts & Assumptions

Given: A smooth rank-r vector bundle π:EM and a smooth map f:NM.

[L1]

A vector bundle chart on E over UM is a diffeomorphism EUU×Rr with transition functions of the form (p,v)(p,gβα(p)v) (Vector bundle charts and transition functions).

[L2]

The restriction EU is the same total space over the smaller open base (Restrictions of vector bundles).

Proof

technique · direct
1.1

Let Φα:EUαUα×Rr be a vector bundle chart. For qf1(Uα) and (q,e)fE, define Φ~α(q,e)=(q,v) when Φα(e)=(f(q),v). This is a bijection (fE)f1(Uα)f1(Uα)×Rr.

L1L2givenconstruct
2.1

On overlaps, Φ~βΦ~α1(q,v)=(q,gβα(f(q))v). These chart changes are smooth and fibrewise linear because the original transition functions are smooth. Therefore the pulled-back charts define a smooth rank-r vector bundle over N.

L1step 1.1algebra

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Dependency tree · two levels

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