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PropositionStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-31
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Assuming countable choice, an ambient metric identifies the two normal bundles

Statement

Assume ACω. Let SM be an embedded submanifold and let g be a Riemannian metric on M. If q:TMSν(S)=TMS/TS is the quotient map, then

qTS:TSν(S)

is a smooth vector-bundle isomorphism. Thus the fixed metric g canonically identifies the quotient normal bundle with its g-orthogonal realization.

Facts & Assumptions

Given: The axiom ACω, an embedded submanifold SM, and an ambient Riemannian metric g on M.

[L0]

Under ACω, TM has a smooth manifold structure for which the induced tangent-bundle charts form a smooth atlas (Assuming countable choice, the tangent bundle has a canonical smooth 2n-manifold structure).

[L4]

An induced tangent-bundle chart sends v=ivixip to (x(p),(v1,,vn)) (The induced tangent bundle chart).

[L5]

A smooth vector bundle is locally trivialized by fibrewise linear charts (Smooth vector bundles, rank, fibres, and trivial bundles).

[L6]

The inclusion i:SM is smooth (The inclusion of an embedded submanifold is a smooth embedding).

[L7]

Pullback along a smooth map carries a smooth vector bundle to a smooth vector bundle (The pullback fibre product is a smooth vector bundle).

[L8]

In a slice chart, S is a coordinate slice (Embedded submanifolds and slice charts).

[L9]

A smooth subbundle is locally spanned by part of a smooth ambient frame (Vector subbundles).

[F0]

A smooth bundle metric is a fibrewise inner product whose pairing of any two smooth local sections is smooth (Smooth bundle metrics).

[L1]

The orthogonal complement of a smooth subbundle is a smooth subbundle (Orthogonal complements of subbundles are smooth subbundles).

[L2]

The quotient map TMSν(S) is a smooth bundle map (The canonical map to a quotient bundle is a smooth bundle map).

[L3]

A fibrewise bijective smooth bundle map over the identity is a bundle isomorphism (A fibrewise bijective smooth bundle map over a diffeomorphism is a bundle isomorphism).

Proof

technique · direct
1.1

By [L0], [L4], and [L5], the induced charts make TMM a smooth vector bundle. By [L6] and [L7], its pullback along i is the smooth vector bundle TMSS. In a slice chart from [L8], its coordinate frame is x1,,xk,y1,,yc and TS is spanned by the first k vectors, so [L9] makes TS a smooth subbundle. In that pulled-back frame, the coefficients of gS are the smooth coefficient functions of g composed with the smooth inclusion i; hence [F0] makes gS a smooth bundle metric on TMS. Applying [L1], the orthogonal complements TSp form a smooth subbundle and fibrewise TpM=TpSTpS.

F0L0L1L4L5L6L7L8L9given
2.1

Restrict the quotient map of [L2] to TS. On each fibre this is the usual linear isomorphism from a chosen complement onto the quotient by TpS. Hence the restricted map TSν(S) is fibrewise bijective, so [L3] shows that it is a smooth bundle isomorphism.

L2L3step 1.1algebra

Depends on

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Sources