Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The canonical map to a quotient bundle is a smooth bundle map

Statement

If SE is a smooth vector subbundle, then the fibrewise quotient map q:EE/S is a smooth vector bundle map over idM, and its kernel is S.

Facts & Assumptions

Given: A smooth vector bundle EM and a smooth subbundle SE.

[L1]

The quotient E/SM is a smooth vector bundle (A vector bundle quotient by a subbundle is a smooth vector bundle).

Proof

technique · direct
1.1

In an adapted local frame (e1,,er) with S spanned by the first k vectors, the quotient bundle chart from [L1] identifies q with the map (p,u,w)(p,w), where uRk and wRrk. Thus q is smooth and fibrewise linear.

L1given
2.1

In the same coordinates, q(p,u,w)=0 exactly when w=0, which means that the vector lies in the span of e1,,ek, namely in Sp. Therefore kerq=S.

step 1.1algebra

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources