Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-31
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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Smooth sections form a module over smooth functions

Statement

If EM is a smooth vector bundle, then the smooth sections of E form a module over C(M) under pointwise addition and scalar multiplication.

Facts & Assumptions

Given: A smooth vector bundle EM.

[L1]

A section is smooth exactly when its local frame components are smooth (Smoothness of a section is equivalent to smooth local components).

Proof

technique · direct
1.1

Let σ,τ be smooth sections and let fC(M). On a local frame, write σ=aisi and τ=bisi with smooth components ai,bi. Then σ+τ=(ai+bi)si and fσ=(fai)si.

L1given
2.1

By [L2], the component functions ai+bi and fai are smooth, so [L1] shows that σ+τ and fσ are again smooth sections. The module axioms hold fibrewise because each fibre is a vector space.

L1L2step 1.1

Depends on

Used by

Dependency tree · two levels

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Sources