Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Every vector in a fibre extends to a compactly supported smooth section

Statement

Let π:EM be a smooth vector bundle, let pM, and let vEp. Then there is a compactly supported smooth section σ of E with σ(p)=v.

Facts & Assumptions

Given: A smooth vector bundle EM, a point pM, and a vector vEp.

[L1]

Around p there is a local frame of E (Local and global frames of a vector bundle).

[L2]

There is a smooth bump function equal to 1 at p and supported in a prescribed chart neighborhood (A chart bump at a point with prescribed support).

[L3]

Multiplying a smooth section by a smooth function keeps it smooth (Smooth sections form a module over smooth functions).

[L4]

A section is smooth exactly when its local frame components are smooth (Smoothness of a section is equivalent to smooth local components).

Proof

technique · direct
1.1

Choose a local frame (s1,,sr) on an open set U containing p. Write v=iaisi(p) and define a local section τ=iaisi on U. Then τ(p)=v.

L1givenchoose
2.1

Choose a smooth bump function χ:MR with χ(p)=1 and supp(χ)U. On U define σ=χτ, which is smooth by [L3]. Because supp(χ)U, there is an open neighborhood V of MU on which χ=0; define σ=0 on V, which is smooth by [L4]. On UV the two formulas agree, so they paste to a smooth global section. Its support is contained in supp(χ), hence compact, and σ(p)=χ(p)τ(p)=v.

L2L3L4step 1.1construct

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources