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PropositionStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
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Linear and angular momentum are conserved by semidiscrete SPH

Statement

Every C¹ solution of Fixed-width regularized conservative SPH particle system conserves total linear momentum P=Σ_im_iv_i and the antisymmetric angular-momentum tensor J=Σ_im_i(q_i⊗v_i−v_i⊗q_i), where (a⊗b)_kl=a_kb_l.

Facts & Assumptions

Given: A C¹ trajectory solving the fixed-width SPH system.

[F1]

Fixed-width regularized conservative SPH particle system: q̇_i=v_i and v̇_i=−Σ_jm_j(A_i+A_j)∇W_ε(q_i−q_j).

[F2]

SPH pressure forces are equal-opposite and central: F_ij=−m_im_j(A_i+A_j)∇W_ε(q_i−q_j); F_ji=−F_ij, F_ij is parallel to q_i−q_j, and ∇W_ε(0)=0.

[F4]

The mean value inequality: if f:[a,b]→Rm is continuous and differentiable on (a,b) with ∥f′∥2≤M, then ∥f(b)−f(a)∥2≤M(b−a): a continuously differentiable vector function with derivative zero on an interval is constant there, by applying the inequality on each closed subinterval.

Proof

1.1F1F2F3algebra

Differentiate P using the finite-sum rule [F3]. The self terms vanish because ∇W_ε(0)=0 by [F2], and grouping the remaining terms by unordered pairs gives Ṗ=Σ_{i<j}(F_ij+F_ji)=0.

2.1F1F2F3F4algebra∎

Differentiate J using the coordinatewise product rule [F3]; the terms v_i⊗v_i cancel, leaving Σ_i(q_i⊗m_iq̈_i−m_iq̈_i⊗q_i). Grouping each pair gives (q_i−q_j)⊗F_ij−F_ij⊗(q_i−q_j)=0 because [F2] makes F_ij parallel to q_i−q_j. Thus J̇=0. Applying [F4] to P and to each component of J on every closed subinterval shows both are constant.

Depends on

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Sources