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PropositionStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-27
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The Stieltjes interval set function is finitely additive on the half-open interval algebra

Statement

Let F:R→R be nondecreasing and right-continuous, and let μ0,F be the set function of The interval set function attached to a nondecreasing right-continuous function. Then the value of μ0,F(E) is independent of the chosen finite disjoint decomposition of E∈H. Moreover, if E,G∈H are disjoint, then

μ0,F(E∪G)=μ0,F(E)+μ0,F(G).

So μ0,F is a finitely additive set function on the half-open interval algebra.

Facts & Assumptions

Given: A nondecreasing right-continuous function F:R→R and the set function μ0,F defined from finite disjoint unions of h-intervals.

[L1]

For every disjoint presentation E=⋃i=1mIi in the half-open interval algebra, the proposed value is μ0,F(E)=∑i=1mμ0,F(Ii). (The interval set function attached to a nondecreasing right-continuous function)

Proof

technique · direct
1.1givenL1

Suppose E=⋃i=1mIi=⋃j=1nJj are two finite disjoint h-interval decompositions of the same set.

Collect every finite endpoint appearing among the Ii and Jj, and adjoin −∞ or +∞ when a left or right ray occurs. This gives an increasing list p0<⋯<pr such that each Ii and each Jj is a disjoint union of consecutive h-cells Cℓ:=(pℓ−1,pℓ], with the first or last cell possibly a ray.

2.1step 1.1L1algebra

If I is one interval from either decomposition, the sum of the μ0,F-values of the consecutive cells inside I telescopes to μ0,F(I).

In the unbounded cases this is exactly the truncation/supremum convention built into The interval set function attached to a nondecreasing right-continuous function. Thus each decomposition gives the same total, namely the sum of the cell values over those Cℓ contained in E. So μ0,F(E) is well defined. [step 1.1, L1, algebra]

3.1step 2.1givenalgebra

Let E,G∈H be disjoint, and choose disjoint h-interval decompositions of E and of G.

Refine them to a common endpoint grid as in step 1.1, and sum over the grid cells. The cells belonging to E∪G are exactly the disjoint union of the cells belonging to E and the cells belonging to G, so the corresponding cell sums add:

μ0,F(E∪G)=μ0,F(E)+μ0,F(G).

Together with step 2.1 this proves the claim. [step 2.1, given, algebra] ∎

Depends on

Used by

Cited to discharge well-definedness by The interval set function attached to a nondecreasing right-continuous function.

Dependency tree · two levels

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Sources