Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The cone construction commutes with shift up to the canonical sign isomorphism

Statement

For every chain map f:CD, there is a canonical chain isomorphism σf:Cone(f[1])Cone(f)[1].

Facts & Assumptions

Given: A chain map f:CD.

[L1]

The shift satisfies C[1]n=Cn1 and dC[1]=dC (The shift of a chain complex).

[L2]

The shifted map satisfies f[1]n=fn1 (Shifted chain maps and shifted chain homotopies).

[L3]

The cone differential is d(y,x)=(d(y)+f(x),d(x)) (The mapping cone of a chain map).

Proof

technique · direct
1.1

The two complexes have the same degree-n object Cone(f[1])n=Dn1Cn2=Cone(f)[1]n. Define σf,n(y,x):=(y,x).

L1L2L3givenconstruct
2.1

By [L1], [L2], and [L3], the differential on Cone(f[1]) is (dD(y)+f(x),dC(x)), while the shifted differential on Cone(f)[1] is (dD(y)f(x),dC(x)). The sign in σf changes the first component exactly enough to intertwine these two formulas, so σf is a chain isomorphism.

L1L2L3step 1.1algebra

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

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