Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-30
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Identities and composites of chain maps are chain maps

Statement

For every chain complex C∙, the identity family 1Cn is a chain map 1C:C→C. If f:C→D and g:D→E are chain maps, then the componentwise composite (gnfn)n is a chain map g∘f:C→E.

Facts & Assumptions

Given: Chain complexes C∙,D∙,E∙ and chain maps f:C→D, g:D→E.

[L1]

A chain map is a degree-zero family commuting with the differentials (Chain map).

Proof

technique · direct
1.1L1givenalgebra

For the identity family, dnC∘1Cn=1Cn−1∘dnC holds trivially in every degree, so [L1] makes 1C a chain map.

2.1L1givenalgebra∎

Since f and g are chain maps, [L1] gives dnEgn=gn−1dnD and dnDfn=fn−1dnC. Therefore dnE(gnfn)=gn−1(dnDfn)=gn−1fn−1dnC, so the composite family again satisfies [L1].

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources