Alphabeta Math
PropositionStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-30
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Homology respects identities and composition

Statement

For every nZ:

  1. Hn(1C)=1Hn(C) for every chain complex C.
  2. If f:CD and g:DE are chain maps, then Hn(gf)=Hn(g)Hn(f).

Facts & Assumptions

Given: Chain maps f:CD and g:DE.

[L1]

Identities and composites of chain maps are chain maps (Identities and composites of chain maps are chain maps).

[L2]

A chain map induces a unique map on homology compatible with the quotient from cycles (A chain map induces a well-defined map on homology).

Proof

technique · direct
1.1

By [L1], 1C is a chain map. The identity on Hn(C) satisfies the same compatibility with the quotient from cycles as the map Hn(1C) from [L2], so uniqueness in [L2] gives Hn(1C)=1Hn(C).

L1L2
2.1

Again by [L1], gf is a chain map. Both Hn(gf) and Hn(g)Hn(f) compose with the cycle quotient to the map induced by the composite on cycles, so [L2] forces them to agree.

L1L2algebra

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources