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TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-08-31
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A chain homotopy equivalence is a quasi-isomorphism

Statement

Every chain homotopy equivalence is a quasi-isomorphism.

Facts & Assumptions

Given: A chain homotopy equivalence f:CD with homotopy inverse g:DC.

[L1]

A chain homotopy equivalence has maps g with gf1C,fg1D (A chain homotopy equivalence).

[L2]

Chain-homotopic maps induce the same map on homology (Chain-homotopic maps induce the same map on homology).

[L3]

Homology respects identities and composition (Homology respects identities and composition).

[L4]

A quasi-isomorphism is a chain map inducing isomorphisms on all homology objects (Quasi-isomorphism).

Proof

technique · direct
1.1

From [L1] and [L2], the homotopies gf1C and fg1D imply Hn(g)Hn(f)=1Hn(C),Hn(f)Hn(g)=1Hn(D) for every nZ.

L1L2givenalgebra
2.1

By [L3], the equalities in step 1.1 say exactly that each Hn(f) has inverse Hn(g). Therefore every Hn(f) is an isomorphism, and [L4] makes f a quasi-isomorphism.

L3L4step 1.1algebra

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources