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PropositionStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passaudited 2026-08-31
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Shift preserves homotopy equivalences, contractibility, and quasi-isomorphisms

Statement

For every integer k, shift preserves chain homotopy equivalences, contractible complexes, and quasi-isomorphisms.

Facts & Assumptions

Given: An integer k.

[L1]

Shift carries chain maps and chain homotopies to shifted ones (Shifted chain maps and shifted chain homotopies).

[L2]

Shift is an autoequivalence on chain complexes and on the homotopy category (Shift is an additive autoequivalence of the complex and homotopy categories).

[L3]

Homology shifts by the rule Hn(C[k])Hnk(C) (Homology of a shift is shifted homology).

[L4]

A quasi-isomorphism is detected degreewise on homology (Quasi-isomorphism).

[L5]

Chain homotopy equivalences are quasi-isomorphisms (A chain homotopy equivalence is a quasi-isomorphism).

[L6]

Contractibility means homotopy equivalence to the zero complex (A contractible complex).

[L7]

A chain homotopy equivalence is a map with a homotopy inverse (A chain homotopy equivalence).

Proof

technique · direct
1.1

If f:CD has homotopy inverse g, then [L1] shifts the homotopies gf1C and fg1D to homotopies g[k]f[k]1C[k],f[k]g[k]1D[k]. The inverse shift [k] from [L2] shows this construction stays inside the same homotopy-equivalence class of objects. Thus [L7] shows that shift preserves chain homotopy equivalences. By [L6], the special case of a homotopy equivalence C0 shows that shift also preserves contractible complexes.

L1L2L6L7givenalgebra
2.1

Let f be a quasi-isomorphism. By [L3], the map Hn(f[k]) identifies with Hnk(f) for every n, so Hn(f[k]) is an isomorphism whenever Hnk(f) is. Then [L4] makes f[k] a quasi-isomorphism. This is compatible with step 1.1 and [L5], since every shifted homotopy equivalence is again a quasi-isomorphism.

L3L4L5step 1.1algebra

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