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The homology Kunneth sequence splits nonnaturally
Statement
Assume AC. For any commutative PID and spaces , the homology Künneth short exact sequence admits an -linear section of its Tor quotient in every degree . Consequently its middle term is abstractly the direct sum of its tensor and Tor terms. The section is constructed after choices; no natural choice of splitting is asserted.
Facts & Assumptions
Topological Kunneth short exact sequence for homology gives the exact sequence .
The PID Kunneth sequence admits a section after choices supplies, for the tensor complex, maps and satisfying , , , and .
Singular product chain equivalence by simplex models supplies the shuffle homology isomorphism with inverse , where . The topological maps of [F1] are , . Assume The Axiom of Choice.
Proof
Given: and the maps in [F1]–[F3], under AC.
The singular complexes are nonnegative free PID complexes, so the section theorem [F2] applies. Define and . Then , , and . All maps are -linear.
The remaining composite satisfies . Therefore and are inverse: one composite is using , and the identity composites; the other is . This proves the direct-sum assertion with the actual cross product and quotient.
The maps of [F2] use chosen retractions and , obtained by splitting the surjections onto and . No splitting of the inclusions is used. Since no compatibility of those retractions with all space maps is supplied, steps 1.1 and 2.1 assert existence of a section, without asserting its naturality. The canonical exact sequence itself retains its naturality from [F1]. This observation alone is not a proof that every possible natural section is impossible.
At , and is the unique map from zero; gives the degree-zero cross-product isomorphism. If a factor is empty, and every formula remains valid. If , the section is the inverse of ; if , no Tor summand is added. In degree zero on a pair of points, sends the tensor of the two unit vertex classes to the unit product vertex class. AC is inherited from [F2] for arbitrary-rank cycle retractions and simultaneous degreewise choices; composing the maps adds no choices.
Depends on
Used by
Dependency tree · two levels
14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Miller, Theorem 25.15, printed page 66 (standard reference, not scraped)