Alphabeta Math
RemarkSession-authored (Fable 5 assisted) sources checked 2026-07-26 not proved here
Recorded, not proved here. This statement is included so the library can refer to it honestly, with a citation to the literature. It is not proved anywhere in this library: the track that would prove it has not been developed here yet.

Holder and Minkowski inequalities in integral form

Statement

Let (X,A,μ) be a measure space and for measurable f put fp:=(Xfpdμ)1/p for 1p<, and f:=ess supXf.

Holder. If 1p,q with 1p+1q=1, then for all measurable f,g,

Xfgdμfpgq.

For 1<p< equality holds exactly when fp and gq are proportional almost everywhere. The case p=q=2 is the Cauchy-Schwarz inequality for the integral.

Minkowski. If 1p, then for all measurable f,g,

f+gpfp+gp.

Hence p is a seminorm on the measurable functions with finite p-th moment, and a norm on the quotient by equality almost everywhere. For 0<p<1 Minkowski's inequality reverses on nonnegative functions and p is not a norm.

Remarks

Not proved in this library. The inequalities are recorded here in their integral form only, and used in no proof here.

What would prove it. Young's inequality abap/p+bq/q, or the concavity of the logarithm, plus the monotonicity and additivity of the Lebesgue integral (Lebesgue measure and the Lebesgue integral ). No convergence theorem is needed; the proofs are the finite-sum proofs with sums replaced by integrals.

Which page it serves. The roots and rational powers page already proves the weighted arithmetic-geometric mean inequality and the finite forms of Holder and Minkowski for finite sequences of reals with rational exponents, and the Rn as a normed space page uses those to get the p-norms on Rn. The integral form is the same statement for the counting measure replaced by an arbitrary measure, and it is exactly the step that needs the integral.

What is genuinely missing here, and what is not. The inequality itself is not deep and its finite version is in scope. What is deferred is the setting: the statement quantifies over measurable functions and uses and ess sup, none of which this library defines. The moment the integral exists, these two lines follow at once, which is why they are recorded together rather than as separate results.

Depends on

Used by

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Sources