Alphabeta Math
RemarkSession-authored (Fable 5 assisted) sources checked 2026-07-26 not proved here
Recorded, not proved here. This statement is included so the library can refer to it honestly, with a citation to the literature. It is not proved anywhere in this library: the track that would prove it has not been developed here yet.

Schechter 2006: Kelley's cofinite proof yields BPI, not the Axiom of Choice

Statement

Kelley (1950) derived the Axiom of Choice from Tychonoff's theorem as follows. Given nonempty sets XaX_a for aIa \in I, adjoin a point \infty to each and topologise Xa{}X_a \cup \{\infty\} by the cofinite topology; each such space is compact, the sets XaX_a are claimed to be closed, and the finite intersection property of the family {πa1(Xa)}\{\pi_a^{-1}(X_a)\} then yields a point of the product, that is, a choice function.

Schechter (2006): that argument does not prove the Axiom of Choice. In the cofinite topology on Xa{}X_a \cup \{\infty\} the set XaX_a is not closed when XaX_a is infinite, since every nonempty open set is cofinite and therefore meets XaX_a. What Kelley's specialisation actually proves, and is equivalent to over ZF, is the Boolean prime ideal theorem.

The repair. Make the adjoined point isolated: topologise Xa{}X_a \cup \{\infty\} as the disjoint sum of XaX_a with its cofinite topology and the one-point space {}\{\infty\}, so that the open sets are the unions of a cofinite subset of XaX_a (or \emptyset) with a subset of {}\{\infty\}. This space is compact and T1T_1, and now XaX_a genuinely is closed, its complement {}\{\infty\} being open. With the repair the classical conclusion survives in the form: "every product of compact T1T_1 spaces is compact" is equivalent to the Axiom of Choice over ZF, while "every product of compact Hausdorff spaces is compact" is equivalent to BPI.

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