Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A V-category is tensored exactly when each covariant hom has a left enriched adjoint

Statement

Assume V is right closed monoidal. A V-category B is tensored if and only if, for every object C of B, the covariant enriched hom-functor B(C,−):B→V has a left enriched adjoint.

Facts & Assumptions

Given: A right-closed monoidal base V, a V-category B, and an object C of it.

[L1]

Tensors of C by objects X∈V are characterized by B(X⊗C,B)≅[X,B(C,B)] (Tensor and cotensor in a V-category).

[L2]

An enriched adjunction is exactly a natural isomorphism of enriched hom-objects (Enriched adjunction).

[L3]

The functor B(C,−) is the representable enriched functor at C (Representable enriched functor).

Proof

technique · direct
1.1L1L2L3given

If B is tensored, then for each X∈V and B∈B the tensor formula of [L1] is exactly the enriched adjunction isomorphism between the functor X↦X⊗C and the representable functor B(C,−) from [L3]. So B(C,−) has a left enriched adjoint.

1.2L1L2L3algebra

Conversely, suppose B(C,−) has a left enriched adjoint LC. Then [L2] gives isomorphisms B(LCX,B)≅[X,B(C,B)] natural in X and B. Comparing with [L1], the object LCX is exactly the tensor X⊗C. So tensors exist for every X and C.

2.1step 1.1step 1.2∎

Hence B is tensored exactly when each covariant hom-functor has a left enriched adjoint.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources