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A coproduct of projectives is projective and a product of injectives is injective
Statement
Assume an abelian category satisfies AB3 and AB3*.
- Every finite coproduct of projective objects is projective, and every finite product of injective objects is injective.
- For an arbitrary small family, the same conclusion holds provided one may choose one lift or one extension for each index in each lifting problem; in particular it holds under the Axiom of Choice.
Facts & Assumptions
Given: An abelian category satisfying AB3 and AB3*, and small families of projective objects and of injective objects.
AB3 and AB3* supply the required coproducts and products (The axioms AB3 and AB3*).
Projective objects are characterized by the lifting property against epimorphisms, and injective objects dually by the extension property against monomorphisms (Projective object characterisations, Injective object characterisations).
Proof
By [L1], let . Given an epimorphism and a morphism , write on the coproduct summands. Because each is projective, [L2] gives a lift of . For a finite family these lifts are chosen explicitly; for an arbitrary small family they are exactly the stated choice-dependent data. The coproduct universal property then assembles the into a lift , so is projective.
The injective claim is dual. By [L1], let . Given a monomorphism and a morphism , write . Each injective object admits an extension by [L2]. The product universal property assembles them into extending . So is injective.
Steps 1.1 and 1.2 prove the finite case without extra choice and the arbitrary small-family case with the stated choice boundary.
Depends on
Used by
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Dependency tree · two levels
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Sources
- Pavel Etingof, Shlomo Gelaki, Dmitri Nikshych, and Victor Ostrik, Tensor Categories, Section 1.6 (standard reference, not scraped)