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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A dual object in the endofunctor category is an adjoint functor

Statement

Let C be a category and write tensor product in its endofunctor category as composition. Then a left dual of an endofunctor F:C→C is exactly a left adjoint of F, and a right dual of F is exactly a right adjoint of F.

Facts & Assumptions

Given: Endofunctors L,F,R:C→C.

[L1]

A left dual of F consists of natural transformations ev⁡:L∘F⇒1C and coev⁡:1C⇒F∘L satisfying the two zig-zag identities (The zig-zag identities).

[L2]

An adjunction L⊣F is a unit 1C⇒F∘L and counit L∘F⇒1C satisfying the two triangle identities (Adjunction by unit, counit, and the triangle identities).

Proof

technique · direct
1.1givenL1L2

Under the tensor-by-composition convention, the data named in [L1] and [L2] are literally the same pair of natural transformations with the same sources and targets.

2.1step 1.1L1L2

The two zig-zag identities for a left dual in the composition monoidal structure are exactly the two triangle identities for an adjunction, because both say that the composites F⇒coev⁡FFLF⇒Fev⁡FandL⇒Lcoev⁡LFL⇒ev⁡LL are identities.

3.1step 2.1∎

Therefore L is a left dual of F exactly when L⊣F. The same comparison with the mirrored data shows that R is a right dual of F exactly when F⊣R.

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources