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A pointwise Kan extension along a fully faithful functor genuinely extends the original functor

Statement

Let K:CD be fully faithful.

If (L,η) is a pointwise left Kan extension of F:CE along K, then for every object c of C the unit component

ηc:F(c)L(Kc)

is an isomorphism.

If (R,ε) is a pointwise right Kan extension of F along K, then for every object c the counit component

εc:R(Kc)F(c)

is an isomorphism.

So a pointwise Kan extension along a fully faithful functor really does restrict back to the original functor.

Facts & Assumptions

Given: A fully faithful functor K:CD; a pointwise left Kan extension (L,η) of F along K; and a pointwise right Kan extension (R,ε) of F along K.

[F1]

A functor is fully faithful when every map C(c,c)D(Kc,Kc) is bijective (Faithful, full, fully faithful, essentially surjective, and split essentially surjective functors).

[F2]

The objects of (KKc) are arrows u:KcKc, and the objects of (KcK) are arrows u:KcKc (Comma category, slice category, and coslice category).

[L1]

A pointwise left Kan extension value is the colimit of the diagram over (KKc), with leg at (c,1Kc) equal to ηc; dually, a pointwise right Kan extension value is the limit over (KcK), with leg at (c,1Kc) equal to εc (Pointwise Kan extensions by the comma-category formula).

[F3]

A colimit over a category with a terminal object is the value at that object, and dually a limit over a category with an initial object is the value there, by the universal property of colimits and limits (Limits and colimits as terminal cones and initial cocones, with existence and uniqueness in their universal properties).

Proof

technique · direct
1.1

In (KKc) the object (c,1Kc) is terminal: for any object (c,u:KcKc), full faithfulness [F1] gives a unique arrow a:cc with K(a)=u, and that arrow is exactly the unique morphism (c,u)(c,1Kc) in the comma category [F2]. Dually, in (KcK) the object (c,1Kc) is initial, by the same full-faithfulness argument.

F1F2
2.1

By [F3], the colimit of the diagram over (KKc) is the value of the diagram at its terminal object (c,1Kc), namely F(c), and the colimit leg there is an isomorphism. Since [L1] identifies L(Kc) with that colimit and ηc with that leg, ηc is an isomorphism. The dual statement for εc follows from the initial object in (KcK) and the limit clause of [F3].

F3L1step 1.1
3.1

Therefore both the left and right pointwise Kan extensions along a fully faithful functor restrict back to the original functor by isomorphism on every object of the image.

step 2.1

Depends on

Used by

Dependency tree · two levels

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Sources