Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-28
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A morphism factors uniquely through its image

Statement

Let f:A→B be a morphism in a category with kernels and cokernels. If c:B→C is a cokernel of f and i:im⁡(f)→B is a kernel of c, then there exists a unique morphism f^:A→im⁡(f) with

i∘f^=f.

Facts & Assumptions

Given: A morphism f:A→B, a cokernel c:B→C of f, and a kernel i:im⁡(f)→B of c.

[L1]

The image of f is the kernel of a cokernel of f (Image and coimage in a category with kernels and cokernels).

Proof

technique · direct
1.1L1given

Because c is a cokernel of f, one has c∘f=0.

2.1L1step 1.1∎

The morphism i is a kernel of c, so step 1.1 gives a unique f^:A→im⁡(f) with if^=f. That is the claimed factorization through the image.

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources