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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04 rests on unproved material (inherited)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Rests on 3 statements not proved in this library, by way of the results it cites. This item cites no such statement directly; it depends on results that do. The unproved premises it inherits are Cohen's first model: an infinite Dedekind-finite set of reals, Sierpiński 1947: the generalised continuum hypothesis implies the Axiom of Choice and The continuum hypothesis and its generalisation are independent of ZFC. Each is recorded with a citation to the literature and is not established here, because the track that would prove it has not yet been developed in this library. Everything else in this proof is proved here.

The acyclic-resolution theorem for left derived functors

Statement

Assume the Axiom of Dependent Choice.

Let P be a supplied projective resolution datum on a class D, let F:AB be an additive right exact functor, and let Q2Q1Q0A0 be an F-acyclic resolution of A relative to P. Assume moreover that AD and that, for Z0:=A and 0Zq+1QqZq0(q0), each Zq lies in D. Then for every n0 there is a canonical isomorphism LnPF(A)  Hn(F(Qdel)).

Facts & Assumptions

Given: An F-acyclic resolution Q1Q0A0 of A relative to P, the associated objects ZqD, and an integer n0.

[L1]

An F-acyclic resolution is an exact augmented complex whose terms are F-acyclic objects (An F-acyclic resolution, An acyclic object for a right exact functor).

[L2]

The zero-th left derived functor of a right exact functor recovers the functor (The zero-th left derived functor of a right exact functor recovers the functor).

[L3]

Change of supplied projective resolution data produces canonical natural isomorphisms of left derived functors (Two supplied projective resolution data define naturally isomorphic left derived functors).

[L4]

Projective resolutions of a short exact sequence can be arranged into a short exact sequence of chain complexes by the projective horseshoe lemma (The horseshoe lemma for projective resolutions).

[L5]

A short exact sequence of chain complexes yields a long exact sequence in homology (The long exact sequence in homology).

Proof

technique · direct
1.1

By exactness in [L1], let Z0=A and for each q0 let Zq+1 fit into a short exact sequence 0Zq+1QqZq0. Every Qq is F-acyclic by [L1].

L1givenconstruct
2.1

Apply [L4] to each short exact sequence from step 1.1 using the supplied projective resolutions of Zq+1 and Zq, which exist by the domain hypothesis in the statement. The middle projective resolution from horseshoe need not be the supplied one for Qq, but [L3] identifies the resulting left derived objects. After applying F and [L5], the higher homology of the middle term vanishes because Qq is F-acyclic, while [L2] identifies the degree-zero term. Thus we obtain exact sequences 0L1PF(Zq)F(Zq+1)F(Qq)F(Zq)0 and isomorphisms LmPF(Zq+1)Lm+1PF(Zq)(m>0).

L2L3L4L5step 1.1algebra
3.1

Repeatedly applying the isomorphisms from step 2.1 gives LnPF(A)=LnPF(Z0)L1PF(Zn1)(n>0).

step 2.1algebra
4.1

For n>0, the exact sequence F(Zn+1)F(Qn)F(Zn)0 from step 2.1 shows that the quotient of F(Qn) by boundaries is F(Zn), and the same step identifies the kernel of F(Zn)F(Qn1) with L1PF(Zn1). Therefore Hn(F(Qdel))L1PF(Zn1)LnPF(A).

step 2.1step 3.1algebra
5.1

For n=0, right exactness gives F(Q1)F(Q0)F(A)0, so H0(F(Qdel))F(A). By [L2], F(A)L0PF(A). Together with step 4.1, this proves the theorem for all n0.

L2step 2.1step 4.1

Depends on

Used by

Dependency tree · two levels

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