Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Coordinate ring of an affine fibre

Statement

Let A→B be a ring map, p∈Spec⁡A, and M=A∖p, acting on B through the ring map. The fibre over p is canonically Spec⁡(B⊗Aκ(p))≅Spec⁡(M−1B/pM−1B). The residue field is κ(p)=Ap/pAp. No reduction of the tensor ring is taken.

Facts & Assumptions

Given: The objects, hypotheses and conventions in the statement above.

[F1]

For a morphism f:X→S and any point s∈S, its scheme-theoretic fibre is Xs=X×SSpec⁡κ(s), viewed as a κ(s)-scheme. The map Spec⁡κ(s)→S is the canonical residue-field point from lem-field-valued-points-of-schemes, and the product is base change as in def-base-change-morphism-schemes. The point s need not be closed. A fibre over a generic point is called a generic fibre. Empty fibres are allowed. (Scheme-theoretic fibre)

[F2]

Let A→B and A→C be maps of commutative unital rings, allowing the zero ring. In the category of all schemes, Spec⁡B×Spec⁡ASpec⁡C≅Spec⁡(B⊗AC). The projections correspond to b↦b⊗1 and c↦1⊗c. (Affine fibre products are spectra of tensor products)

[F3]

Let A→C be a unital ring map. For any set of variables (ti) and any ideal I⊆A[ti], (A[ti]/I)⊗AC≅C[ti]/IC[ti]. Here the extended ideal is generated by the coefficient images of all elements of I. For a multiplicative subset M⊆A, (M−1A)⊗AC≅M‾−1C. These are ring isomorphisms; no flatness, finite-generation or nonzero-ring hypothesis is required. (Presentations and localization under base extension)

Proof

1.1givenF1F2

F1 defines the fibre as base change by Spec⁡κ(p). F2 therefore gives its coordinate ring B⊗Aκ(p).

2.1F3step 1.1

Write κ(p)=Ap/pAp. Localizing coefficients and then imposing the ideal relations, using F3, identifies the ring with M−1B/pM−1B. The maps send b⊗(a/s mod p) to ab/s mod p.

3.1step 2.1algebra∎

The formula preserves every element, including nilpotents. If the quotient is zero the fibre is empty; otherwise its primes and residue fields are retained. For p=(0) in a domain it is extension to the fraction field, and for B=A it is the one-point spectrum of κ(p).

Depends on

Used by

Dependency tree · two levels

10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources