Alphabeta Math
TheoremStatement: Literature-sourcedProof: Literature-sourcedprecheck passaudited 2026-08-13
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An is simple for every n≥5

Statement

The alternating group An is simple for every n≥5.

Facts & Assumptions

Given: n≥5.

[F1]

A group is simple when it is nontrivial and its only normal subgroups are the trivial subgroup and the whole group (Simple groups).

[F2]

Every nontrivial normal subgroup of An contains a 3-cycle (Every nontrivial normal subgroup of An contains a 3-cycle for n≥5).

[F3]

A normal subgroup of An containing a 3-cycle is all of An (A normal subgroup of An containing one 3-cycle equals An for n≥5).

Proof

technique · direct
1.1

The cycles (1 2 3) and (3 4 5) have sign (−1)2=+1 by [F4], so they belong to An; they do not commute, so An is nontrivial.

F4algebra
1.2

Let N⊴An. If N is nontrivial, [F2] gives a 3-cycle in N, and [F3] then gives N=An.

F2F3
2.1

Thus the only normal subgroups are {1} and An; together with step 1.1, [F1] proves simplicity.

F1step 1.1step 1.2∎

Depends on

Used by

Dependency tree · two levels

15 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources