Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
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A5 and Sn for n≥5 are not solvable

Statement

The alternating group An is not solvable for every n≥5. Consequently Sn is not solvable for every n≥5; in particular, A5 and S5 are not solvable.

Facts & Assumptions

Given: An integer n≥5.

[F1]

A group is solvable exactly when its derived series reaches the trivial group (The derived series, solvable groups, and derived length).

[L1]

Every subgroup of a solvable group is solvable (Subgroups and quotients of solvable groups are solvable).

[L2]

An is simple for every n≥5 (An is simple for every n≥5).

[L3]

For n≥5, An′=An; also Sn′=An ([Sn,Sn]=An for n≥2, and [An,An]=An for n≥5).

Proof

technique · direct
1.1

By [L3], every positive term of the derived series of An equals An, which is nontrivial by [L2]; hence the series never reaches 1, and An is not solvable by [F1].

givenL2L3F1
2.1

Since An≤Sn, solvability of Sn would imply solvability of An by [L1], contradicting step 1.1.

step 1.1L1
3.1

Therefore An and Sn are nonsolvable for all n≥5, including n=5.

step 1.1step 2.1∎

Depends on

Used by

Dependency tree · two levels

17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources