Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-28
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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An abelian category is balanced

Statement

If f:AB in an abelian category is both monic and epic, then f is an isomorphism.

Facts & Assumptions

Given: An abelian category and a morphism f:AB that is both monic and epic.

[L1]

The kernel of a monomorphism is zero, and the cokernel of an epimorphism is zero (The kernel of a monomorphism is zero and the cokernel of an epimorphism is zero).

[L2]

The cokernel of 0A is A, and the kernel of B0 is B (The cokernel of the zero map out of the zero object is the target, and dually for kernels).

[L3]

Every morphism has a canonical factorization Acoim(f)im(f)B (The canonical morphism from the coimage to the image exists and is unique).

[L4]

In an abelian category the canonical map coim(f)im(f) is an isomorphism (Abelian category).

Proof

technique · direct
1.1

Because f is monic and epic, [L1] identifies ker(f) and coker(f) with zero objects. Hence [L2] gives isomorphisms qf:Acoim(f) and if:im(f)B for the coimage projection and image inclusion of f.

L1L2L3
2.1

By [L4], the middle map f:coim(f)im(f) is an isomorphism. Since f=iffqf, step 1.1 shows that f is a composite of three isomorphisms, so f itself is an isomorphism.

L3L4step 1.1

Depends on

Used by

Dependency tree · two levels

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Sources