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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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Artin's fixed-field theorem: [K:KG]=G and Aut(K/KG)=G

Statement

If G is a finite group of automorphisms of K, then [K:KG]=G and Aut(K/KG)=G.

Facts & Assumptions

Given: A field K, a finite automorphism group G, and the fixed field KG.

[L1]

If G is a finite group of automorphisms of K, then [K:KG]G (Artin's fixed-field lower bound [K:KG]G).

[L2]

If G is a finite group of automorphisms of K, then [K:KG]G (Artin's fixed-field upper bound [K:KG]G).

[L3]

For a finite extension K/E, one has Aut(K/E)[K:E] (Aut(K/F) is a group and Aut(K/F)[K:F]s[K:F]).

Proof

technique · direct
1.1

The opposing bounds [L1] and [L2] give [K:KG]=G. In particular K/KG is finite. For G={1} this says KG=K and the degree is 1.

L1L2
2.1

Every σG fixes KG, so GAut(K/KG). By [L3] and step 1.1, Aut(K/KG)[K:KG]=G; a finite set containing G and having at most its cardinality equals G.

step 1.1L3algebra

Depends on

Used by

Dependency tree · two levels

10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources