Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Artin's fixed-field theorem: [K:KG]=∣G∣ and Aut⁡(K/KG)=G

Statement

If G is a finite group of automorphisms of K, then [K:KG]=∣G∣ and Aut⁡(K/KG)=G.

Facts & Assumptions

Given: A field K, a finite automorphism group G, and the fixed field KG.

[L1]

If G is a finite group of automorphisms of K, then [K:KG]≥∣G∣ (Artin's fixed-field lower bound [K:KG]≥∣G∣).

[L2]

If G is a finite group of automorphisms of K, then [K:KG]≤∣G∣ (Artin's fixed-field upper bound [K:KG]≤∣G∣).

[L3]

For a finite extension K/E, one has ∣Aut⁡(K/E)∣≤[K:E] (Aut⁡(K/F) is a group and ∣Aut⁡(K/F)∣≤[K:F]s≤[K:F]).

Proof

technique · direct
1.1L1L2

The opposing bounds [L1] and [L2] give [K:KG]=∣G∣. In particular K/KG is finite. For G={1} this says KG=K and the degree is 1.

2.1step 1.1L3algebra∎

Every σ∈G fixes KG, so G⊆Aut⁡(K/KG). By [L3] and step 1.1, ∣Aut⁡(K/KG)∣≤[K:KG]=∣G∣; a finite set containing G and having at most its cardinality equals G.

Depends on

Used by

Dependency tree · two levels

10 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources