Alphabeta Math
TheoremStatement: Literature-sourcedProof: Literature-sourcedPipeline-generatedprecheck pass
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Balanced pairwise summation has a depth-dependent error bound

Statement

Let x1,…,xn∈R, n≥1, be successfully processed by Balanced pairwise summation with range-failure status in the operationwise model. Put d=⌈log⁡2n⌉, assume du<1, and set γd=du/(1−du). Then ∣s^−∑i=1nxi∣≤γd∑i=1n∣xi∣. For n=1, d=0 and the error is zero.

Facts & Assumptions

Given: the successful padded balanced tree and operationwise model.

[F1]

Balanced pairwise summation with range-failure status: the tree has depth d and rounds each internal addition.

[F2]

If |delta_i| <= u and n u < 1, then prod (1+delta_i) = 1 + theta_n with |theta_n| <= gamma_n: a product of k relative factors is within gamma_k of 1 when ku<1.

Proof

1.1givenF1choose

Each original leaf contributes along one path of at most d rounded additions; zero padding contributes zero. Expanding the additions by the relative model writes s-hat=sum_i x_i product_{r=1}^{k_i}(1+delta_ir), with k_i<=d and |delta_ir|<=u.

2.1step 1.1F2algebra∎

For k_i=0 the product is 1. Otherwise [F2] bounds its difference from 1 by gamma_{k_i}<=gamma_d. Subtracting the exact sum and applying the triangle inequality proves the result; for d=0 every input is the sole exact leaf.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources