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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-14
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The basic Cohen model satisfies BPI and fails Choice

Statement

Let M be a transitive model of ZFC, let G be M-generic for Add(ω,ω)M, and let N=HSG be the finite-support basic Cohen symmetric model. Then N is a transitive model of

ZF+BPI+¬AC.

Its symmetric set A of coordinate Cohen reals is infinite and Dedekind-finite, and in particular is not well-orderable in N.

Facts & Assumptions

Given: The ground, generic, and model in the Statement.

[F1]

The basic Cohen symmetric system defines N and its coordinate set A.

[F2]
[F3]

Search-and-shift prime-ideal construction in the basic Cohen model proves inside this exact hereditarily symmetric presentation that every proper set filter extends to an ultrafilter and hence that BPI holds.

[F4]

The basic Cohen model fails well-orderability and AC proves that A is infinite, Dedekind-finite, not well-orderable, and that AC fails in N.

[F5]

The Boolean prime ideal principle and The Axiom of Choice fix the two object-theory assertions.

Proof

technique · composition of the symmetric-model, BPI, and failure-of-choice modules
1.1

F1 and F2 give a transitive model N of every ZF axiom.

F1F2
2.1

F3 applies to the same M, G, finite-permutation group, normal filter, and class of hereditarily symmetric names, so N satisfies the BPI assertion of F5. This route does not use the unsupported promotion of a parameter-definable maximal ideal in the Repický shortcut.

F3F5step 1.1
2.2

F4 applies to the same orbit set A and shows internally that A is infinite and Dedekind-finite. A well-order would enumerate its least unused elements and contradict Dedekind-finiteness, so A is not well-orderable; by F5, AC would well-order it. Thus N¬AC.

F4F5step 1.1
3.1

Combining steps 1.1, 2.1, and 2.2 gives NZF+BPI+¬AC. The ground-model AC used by the search-and-shift construction is a metatheoretic construction hypothesis and is not asserted in N.

step 1.1step 2.1step 2.2

Depends on

Used by

Dependency tree · two levels

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Sources