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Bernstein polynomials converge uniformly to every continuous function on
Statement
If is continuous, then uniformly on .
Facts & Assumptions
Given: A continuous function and .
A continuous function on a compact metric space is uniformly continuous (Heine-Cantor: a continuous map from a compact metric space to any metric space is uniformly continuous).
The Bernstein basis has the zeroth and centred second moment identities (The zeroth, first, and second centred moments of the Bernstein basis).
For each positive real there is a natural with (For every in a complete ordered field there is a natural with ).
Proof
Choose such that whenever , and choose with .
On the far part, ; hence its total basis weight is at most by [L2].
Split the Bernstein sum into and its complement. The near part is at most by the zeroth identity.
Choose so large that . The far part is then below , uniformly in .
The near and far estimates give for every and all sufficiently large .
Depends on
Used by
Dependency tree · next 3 levels
Direct dependencies and their dependencies through the next three levels: 58 results over 16 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.
Sources
- Bernstein polynomial (Encyclopedia of Mathematics) (standard reference, not scraped)