Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
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Bilinear forms on V correspond linearly and bijectively to linear maps V→V∗

Statement

The assignment

B⟼B♭,B♭(v)(w)=B(v,w),

is a linear bijection from the vector space of bilinear forms on V to L(V,V∗).

Facts & Assumptions

Given: An F-vector space V.

[L1]

A bilinear form is linear separately in both variables (Bilinear forms, and symmetric, skew-symmetric, and alternating bilinear forms).

[L2]

The algebraic dual V∗ consists of all linear maps V→F (Linear functionals and the algebraic dual V∗=L(V,F)).

[L3]

Linear maps form a vector space under pointwise addition and scalar multiplication (The space L(V,W) of linear maps with pointwise addition and scalar multiplication).

Proof

technique · explicit inverse
1.1

For a bilinear B, fixing v makes w↦B(v,w) a member of V∗ by [L1] and [L2], and linearity in v makes B♭:V→V∗ linear.

L1L2
1.2

Conversely, for L∈L(V,V∗), define BL(v,w)=L(v)(w). Linearity of L gives linearity in v, and L(v)∈V∗ gives linearity in w, so BL is bilinear.

L1L2L3
2.1

Pointwise, BB♭(v,w)=B(v,w) and (BL)♭(v)(w)=L(v)(w), so the constructions are inverse. They also preserve addition and scalar multiplication pointwise.

step 1.1step 1.2L3algebra
3.1

Therefore B↦B♭ is a linear bijection. No finite-dimensionality assumption is used.

step 2.1∎

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources