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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
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Alternating forms are skew-symmetric; the converse holds when charF2, while in characteristic 2 alternating forms are symmetric

Statement

Every alternating bilinear form is skew-symmetric. If charF2, every skew-symmetric bilinear form is alternating. If charF=2, every alternating bilinear form is symmetric.

Facts & Assumptions

Given: A bilinear form B:V×VF.

[L1]

Alternating means B(v,v)=0 for all v, skew-symmetric means B(u,v)=B(v,u), and symmetric means B(u,v)=B(v,u) (Bilinear forms, and symmetric, skew-symmetric, and alternating bilinear forms).

[L2]

The characteristic is the least positive natural multiple of 1F that is zero, or 0 if none exists (The characteristic of a ring: the least n1 with n1R=0 when one exists, and 0 otherwise); a field has 0F1F and every nonzero element is invertible (Field).

Proof

technique · direct
1.1

If B is alternating, bilinearity gives 0=B(u+v,u+v)=B(u,v)+B(v,u), so B(u,v)=B(v,u) and B is skew-symmetric.

L1algebra
1.2

If B is skew-symmetric, then B(v,v)=B(v,v), so 2B(v,v)=0. When charF2, [L2] makes 2=1F+1F nonzero and invertible, giving B(v,v)=0 for every v and hence alternation.

L1L2algebra
2.1

If charF=2 and B is alternating, [L2] gives 1F+1F=0F and hence a=a for every aF. Step 1.1 therefore gives B(u,v)=B(v,u)=B(v,u), so B is symmetric.

step 1.1L1L2algebra
3.1

These arguments prove each asserted implication without claiming that every symmetric form in characteristic 2 is alternating.

step 1.1step 1.2step 2.1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 48 results over 15 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources