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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-12
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BPP amplification to inverse-polynomial error

Statement

If LBPP and q is a polynomial with positive values on N, then L also has a probabilistic polynomial-time decider whose error on length-n inputs is at most 1/q(n).

Facts & Assumptions

Given: a language LBPP and a positive polynomial q.

[L1]

A BPP machine is correct on every input with probability at least 2/3 (The classes RP, coRP, ZPP, BPP, and PP).

[L2]

Repeating such trials independently and taking the majority answer makes the error probability at most 9/k after k repetitions (Chebyshev bounds the majority error of repeated Bernoulli trials).

Proof

technique · direct
1.1

Let M be a BPP machine for L. On input x, run M independently k:=9q(x) times and output the majority answer. Each run uses polynomial time and k is polynomial in x, so the new machine is still probabilistic polynomial-time.

L1givenconstruct
2.1

Fix x. The correctness indicators of the independent runs satisfy the hypotheses of [L2] by [L1], so the probability that the majority answer is wrong is at most 9/k1/q(x).

L1L2step 1.1algebra
3.1

Since x was arbitrary, the amplified machine has inverse-polynomial error on every input length.

step 2.1

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources