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BPP amplification to inverse-polynomial error
Statement
If and is a polynomial with positive values on , then also has a probabilistic polynomial-time decider whose error on length- inputs is at most .
Facts & Assumptions
Given: a language and a positive polynomial .
A BPP machine is correct on every input with probability at least (The classes RP, coRP, ZPP, BPP, and PP).
Repeating such trials independently and taking the majority answer makes the error probability at most after repetitions (Chebyshev bounds the majority error of repeated Bernoulli trials).
Proof
Let be a BPP machine for . On input , run independently times and output the majority answer. Each run uses polynomial time and is polynomial in , so the new machine is still probabilistic polynomial-time.
Fix . The correctness indicators of the independent runs satisfy the hypotheses of [L2] by [L1], so the probability that the majority answer is wrong is at most .
Since was arbitrary, the amplified machine has inverse-polynomial error on every input length.
Depends on
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Eric Blais, Models of Computation, 14. Randomized Computation (standard reference, not scraped)
- Sanjeev Arora and Boaz Barak, Computational Complexity: A Modern Approach (standard reference, not scraped)