Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-13
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Similar matrices have the same characteristic polynomial

Statement

If A,B∈Mn(F) are similar, then χA(x)=χB(x) in F[x], including n=0.

Facts & Assumptions

Given: Similar matrices A,B∈Mn(F).

[L1]

Similarity means that B=P−1AP for some invertible P∈Mn(F) (Similar matrices: B=P−1AP for an invertible P).

[L2]

For positive size over a commutative ring, det⁡(XY)=det⁡(X)det⁡(Y) (For same-sized finite square matrices over a commutative ring, det⁡(AB)=det⁡(A)det⁡(B)).

[L3]

Field matrices embed entrywise into matrices over F[x], with the same matrix arithmetic and determinant (For a field, the ring-matrix operations, invertibility and similarity agree exactly with the established field-matrix interface).

Proof

technique · direct
1.1

If n=0, [L4] gives χA=1=χB.

L4
1.2

Suppose n≥1 and choose P from [L1]. Over F[x], xI−B=P−1(xI−A)P.

L1L3algebra
2.1

By [L2], det⁡(xI−B)=det⁡(P−1)det⁡(xI−A)det⁡(P). Since P−1P=I, multiplicativity also gives det⁡(P−1)det⁡(P)=1.

step 1.2L2L3algebra
3.1

Using [L4] in step 2.1 gives χB(x)=χA(x), and step 1.1 supplies the remaining size.

step 1.1step 2.1L4∎

Depends on

Used by

Dependency tree · two levels

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Sources