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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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The class equation G=Z(G)+i[G:CG(xi)]|G|=|Z(G)|+\sum_i [G:C_G(x_i)] for a finite group

Statement

Let GG be finite, and let x1,,xrx_1,\ldots,x_r contain one representative from each conjugacy class having more than one element. Then

G=Z(G)+i=1r[G:CG(xi)].|G|=|Z(G)|+\sum_{i=1}^{r}[G:C_G(x_i)].

Facts & Assumptions

Given: A finite group GG and representatives x1,,xrx_1,\ldots,x_r of its non-singleton conjugacy classes.

[L4]

The center is Z(G)={zG:zg=gz for every gG}Z(G)=\{z\in G:zg=gz\text{ for every }g\in G\} (The center Z(G)Z(G) of a group).

Proof

technique · direct
1.1

Let GG act on itself by conjugation. By [L1] and [L3], its orbits are the conjugacy classes and they partition GG.

L1L3
2.1

The class of xx is a singleton exactly when gxg1=xgxg^{-1}=x for every gg, equivalently when xZ(G)x\in Z(G) by [L4]. Thus the singleton classes contribute Z(G)|Z(G)|.

step 1.1L3L4
3.1

Applying the finite partition sum rule to the singleton classes and to the classes represented by x1,,xrx_1,\ldots,x_r gives G=Z(G)+i=1rClG(xi)|G|=|Z(G)|+\sum_{i=1}^{r}|\operatorname{Cl}_G(x_i)|.

step 1.1step 2.1L5L6
4.1

Replacing each remaining class size by [L2] yields G=Z(G)+i=1r[G:CG(xi)]|G|=|Z(G)|+\sum_{i=1}^{r}[G:C_G(x_i)].

step 3.1L2

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 97 results over 21 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources