Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A classical master solution defines a square-zero differential

Statement

Let (A,Δ) be as in BV algebra with a degree-one generator, and let S∈A0 satisfy the classical master equation in Classical and formal quantum master equations. Then dS:A→A, dS(a)={S,a}, has degree +1 and satisfies dS2=0.

Facts & Assumptions

Given: A BV algebra over a characteristic-zero field, an element S∈A0, and the CME {S,S}=0.

[F1]

Classical and formal quantum master equations: the classical master equation for a degree-zero element S is {S,S}=0.

[F2]

The derived BV bracket is an odd Poisson bracket: the bracket has degree +1 and satisfies {a,{b,c}}={{a,b},c}+(−1)(∣a∣+1)(∣b∣+1){b,{a,c}}.

Proof

1.1givenF2algebra

Since the bracket has degree +1 by [F2] and ∣S∣=0, the map dS(a)={S,a} sends Ar into Ar+1 and has degree +1.

1.2givenF2algebra

Apply the Jacobi identity [F2] with a=b=S and third entry x; its sign is (−1)(0+1)(0+1)=−1, so {S,{S,x}}={{S,S},x}−{S,{S,x}} and therefore 2dS2(x)={{S,S},x}.

2.1givenF1step 1.2algebra∎

The CME [F1] makes the right side zero. Characteristic zero makes 2 invertible, hence dS2(x)=0 for every x∈A.

Depends on

Used by

Dependency tree · one level

3 results within one dependency step of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources