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A closed unital real function algebra is C(Y,R) on its indistinguishability quotient

Statement

Let X be a compact Hausdorff space and let AC(X,R) be a uniformly closed unital real function algebra. Let YA=X/A be its indistinguishability quotient and qA:XYA the canonical projection (The quotient that identifies points indistinguishable by a real function algebra). Then YA is compact Hausdorff, every fA descends uniquely to a continuous f~C(YA,R) with f=f~qA, and AC(YA,R),ff~, is a unital algebra isomorphism. When X is nonempty it is also isometric for the uniform metric, which For a nonempty set X and a metric space (Y,d) the uniform metric ρˉ(f,g)=supxmin{d(f(x),g(x)),1} is a metric on YX defines only on a nonempty domain. Thus A is canonically the full continuous real function algebra on the quotient whose points it separates.

Facts & Assumptions

Given: A compact Hausdorff space X, a uniformly closed unital real function algebra AC(X,R), its indistinguishability quotient YA, and the canonical surjection qA:XYA.

[L1]

The relation xAy means f(x)=f(y) for every fA, and YA=X/A carries the quotient topology of qA (The quotient that identifies points indistinguishable by a real function algebra).

[L2]

For a quotient map q:XY, a set VY is open exactly when q1[V] is open in X (The quotient topology of a surjection, quotient maps, saturated sets, and the quotient of a space by an equivalence relation with its canonical projection).

[L4]

Every unital point-separating real function algebra on a compact Hausdorff space is uniformly dense in the full continuous real function space (Real Stone–Weierstrass theorem for compact Hausdorff spaces).

[L5]
[L6]

The function dR(s,t)=st is a metric on R, and its metric topology is the usual topology (The absolute value makes R a metric space: d(x,y)=xy is a metric, its open balls are the intervals (xr,x+r), and it is unbounded).

[L7]

In every metric space, distinct points have disjoint open balls; hence every metric space is Hausdorff (Distinct points of a metric space have disjoint balls around them).

[L8]

For a nonempty set X and a metric space (Y,d), the uniform metric on YX is ρˉ(f,g)=supxXmin{d(f(x),g(x)),1} (For a nonempty set X and a metric space (Y,d) the uniform metric ρˉ(f,g)=supxmin{d(f(x),g(x)),1} is a metric on YX).

Proof

technique · direct
1.1

For fA, [L1] makes f constant on each fibre of qA, so there is a unique function f~:YAR satisfying f=f~qA.

L1given
1.2

The quotient map qA is continuous and surjective by [L2], so [L3] makes YA=qA[X] compact.

L2L3
2.1

For every open UR, one has qA1[f~1[U]]=f1[U], which is open because f is continuous; [L2] therefore makes f~ continuous.

step 1.1L2
2.2

The descent map is an injective unital algebra homomorphism, because descent respects the pointwise operations and f=f~qA determines f~ on the surjective image. When X is nonempty it is moreover isometric: qA is onto, so the two families of values coincide and supxXg(qA(x))h(qA(x))=supyYAg(y)h(y). For X= both function spaces have the unique empty function as their only member, so the map is a bijection; no isometry is asserted there, since [L8] defines the uniform metric only on a nonempty domain.

step 1.1L8algebra
3.1

If [x]A[y]A, then [L1] supplies fA with f(x)f(y). By [L6] and [L7], the distinct real values f~([x]A) and f~([y]A) have disjoint open neighbourhoods; their inverse images under the continuous f~ are disjoint open neighbourhoods of the two classes, so YA is Hausdorff by [L5].

L1step 2.1L5L6L7
3.2

The descended family A~:={f~:fA} is a unital real function algebra because descent respects the pointwise operations, and it separates points by the definition of A in [L1].

step 1.1step 2.1L1algebra
4.1

Since YA is compact Hausdorff by steps 1.2 and 3.1, [L4] makes A~ uniformly dense in C(YA,R).

step 1.2step 3.1step 3.2L4
5.1

For gC(YA,R) and ε>0, step 4.1 supplies fA with f~(y)g(y)<ε for every yYA; since f=f~qA, the same bound reads f(x)g(qA(x))<ε for every xX, so gqA is uniformly approximable by members of A. As A is uniformly closed, gqAA, and its unique descent in step 1.1 is g because qA is surjective. Hence the descent map is surjective, and with step 2.2 it is the claimed unital algebra isomorphism, isometric whenever X.

step 1.1step 4.1step 2.2given

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