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The continuous ODE adjoint gives the parameter gradient with endpoint terms
Statement
Assume . Let solve the parameter-dependent ODE of Parameter-dependent ODE flows have the variational tangent on a common tube on . Let where and are on a neighborhood of the trajectory tube and their first derivatives are bounded and uniformly continuous there. Let be the tangent from that lemma. Let solve the terminal adjoint problem Then This formula separates initial, terminal, running-cost and vector-field parameter terms. It applies only while the common-tube and differentiability hypotheses hold.
Facts & Assumptions
Given: , the common-tube ODE, initial map, objective, and bounded uniformly continuous first derivatives in the Statement.
Parameter-dependent ODE flows have the variational tangent on a common tube: the parameter flow is and , .
Linear matrix ODEs have unique global solutions on a fixed interval: a continuous coefficient linear matrix IVP has a unique solution on the full compact interval.
The total-derivative chain rule differentiates a composition of Euclidean maps (The chain rule for total derivatives: ).
All objective derivatives and ODE derivative coefficients are continuous and bounded on the common compact tube, and their first derivatives have the uniform continuity needed to differentiate the integral objective.
Proof
Fix and write and . The coefficient matrix is continuous. Apply [F3] with initial time to the homogeneous matrix equation , choosing an initial matrix whose first column is and whose other columns are zero. Its first column is and solves the terminal adjoint equation. Any other solution embeds as a column of such a matrix solution, so uniqueness in [F3] gives uniqueness of .
By [F1] and the chain rule [F4], the terminal derivative is . For the running term, a parameter increment gives uniformly in by [F1]. Uniform continuity of the objective derivatives on the common compact tube gives a uniform first-order remainder along the segment from to ; the common integrable majorant permits integration of this remainder. Applying [F4] pointwise and integrating therefore gives the running derivative . Consequently .
In [F2], set , , and . The adjoint equation in the Statement and tangent equation in [F1] satisfy its hypotheses. Transposing that row pairing identity and using gives
Substitute step 1.3 into step 1.2; the terms involving cancel, leaving the asserted continuous adjoint gradient formula.
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Sources
- William W. Hager, Runge-Kutta methods in optimal control and the transformed adjoint system, §3 (standard reference, not scraped)
- Hannes Meinlschmidt, Optimization with Partial Differential Equations, complete lecture notes, Chapter 3 (standard reference, not scraped)
- Michael B. Giles and Niles A. Pierce, An Introduction to the Adjoint Approach to Design, §2.4 (standard reference, not scraped)