Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)
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Covariant derivative along a curve is independent of frame and extension

Statement

The operator Dt is independent of local frames. If V=sγ near a parameter value for an ambient local section s, then DtV=(s)γ(t)(γ˙(t)). Consequently any two such extensions give the same derivative. This is an agreement assertion when an ambient extension exists, not an assertion that every section along a curve extends.

Facts & Assumptions

Given: A connection, a smooth curve and a section of its pullback bundle, with the endpoint convention in the derivative definition.

[F1]

Dt is pullback covariant differentiation in direction t (Covariant derivative along a curve).

[F2]

The pullback connection is frame independent and differentiates pulled-back ambient sections by the differential of the base map (Pullback connection is well defined and functorial).

Proof

1.1

The connection γ is intrinsically well defined, so its evaluation on the globally specified vector field t is frame independent. Apply the ambient-section identity in [F2] with f=γ and X=t; its differential is γ˙(t), giving the displayed formula.

F1F2
2.1

If s1γ=s2γ=V on a parameter neighbourhood, both displayed derivatives equal the same DtV, proving independence of the extension. At an included endpoint, equality on the one-sided interval makes the derivative equality hold by the endpoint convention. For a constant curve at p, V(t)=tv with v0 is a valid section with DtV=v, but no ambient extension can have these varying values at p. Zero sections and rank zero cause no exception. No ambient extension is selected in defining Dt, so this statement uses no choice principle.

F1step 1.1

Depends on

Used by

Dependency tree · two levels

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Sources