Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Strong convexity converts transcription objective error into a control bound

Statement

Let u∗ minimize the LQR objective J on a convex feasible set F, with control weight R(t)⪰rI for r>0. Let uN∈F and let vN∈F be a recovered comparison control. Suppose the computed objective JN satisfies ∣JN(w)−J(w)∣≤δN for w=uN,vN, and JN(uN)≤JN(vN)+ηN. If J(vN)≤J(u∗)+ρN, then J(v)−J(u∗)≥r2∥v−u∗∥22 for every v∈F, and 0≤J(uN)−J(u∗)≤2δN+ηN+ρN,∥uN−u∗∥L2≤2(2δN+ηN+ρN)r. The conclusion is conditional on the stated objective consistency and comparison bounds. A raw embedded RK error estimate is not a certified value of δN.

Here are sufficient bounds that derive the two error terms from transcription errors and recovery. Set Cs=e∥A∥∞T∥B∥∞T, Mc=sup⁡c∈Uc∥c∥2, Mx=e∥A∥∞T(∥x0∥2+∥B∥∞TMc), E=TMx+∥xd∥2, and MT=Mx+∥xT∥2. Suppose, for w=uN,vN, a pointwise representative and sampling rule are fixed, JN(w) has the form JN(w)=∑kωNkℓ~N,w(τNk)+12(x~N[w](T)−xT)TP(x~N[w](T)−xT), where ℓ~N,w(t)=12((x~N[w](t)−xd(t))TQ(t)(x~N[w](t)−xd(t))+w(t)TR(t)w(t)), ωNk≥0, ∑kωNk=T, and the chosen samples satisfy ∥Q(τNk)∥2≤∥Q∥∞. Suppose ∥x~N[w]−xw∥∞≤eN, ∥xw(τNk)−xd(τNk)∥2≤EN, ∥xw(T)−xT∥2≤MT, and ∣∑kωNkℓw(τNk)−∫0Tℓw(t)dt∣≤qN, where ℓw(t)=12((xw(t)−xd(t))TQ(t)(xw(t)−xd(t))+w(t)TR(t)w(t)). Then one may take δN=qN+T2∥Q∥∞(2EN+eN)eN+12∥P∥(2MT+eN)eN. If a feasible recovery sequence also satisfies ∥vN−u∗∥2≤σN, then one may take ρN=CJσN, where CJ=∥Q∥∞ETCs+∥P∥MTCs+MTMc, with M any essential upper bound for ∥R(t)∥2. In the control-only case, under Countable Choice the cell-average lemma supplies vN=PNu∗ and σN→0. If u∗ is Lipschitz with constant Lu, then σN=TLuhN is a valid rate for mesh size hN. For a general L2 minimizer, no rate for σN is asserted.

Facts & Assumptions

Given: The LQR model, r>0, a continuous minimizer, two feasible controls, and the finite objective inequalities in the Statement. For the explicit numerical-error estimate, also assume the stated pointwise sampling, state, and quadrature bounds.

[F1]

The state map is affine and bounded from L2 to the supremum norm (The bounded measurable linear ODE has a unique affine state map).

[F2]

Expanding the LQR quadratic forms for d=v−u gives J(v)−J(u)=Gu[d]+12∫0T(δxTQδx+dTRd)dt+12δx(T)TPδx(T), where δx=xv−xu and Gu[d]=∫0T((xu−xd)TQδx+uTRd)dt+(xu(T)−xT)TPδx(T); this follows from [F1] and the definition of J (Finite-horizon bounded-control linear-quadratic ODE problem, The bounded measurable linear ODE has a unique affine state map).

[F3]

For admissible controls, ∥u∥2≤TMc and ∥xu∥∞≤Mx by compactness of Uc and the state-map bound (Finite-horizon bounded-control linear-quadratic ODE problem, The bounded measurable linear ODE has a unique affine state map).

[A1]

Countable Choice is assumed only for the control-only cell-average recovery specialization (The Axiom of Countable Choice (ACω), Cell averages give a strong recovery sequence for compact convex controls).

Proof

1.1F2givenalgebra

Fix v∈F and put d=v−u∗. Convexity gives u∗+θd∈F for 0≤θ≤1. By [F2], J(u∗+θd)−J(u∗)=θGu∗[d]+θ2Rd, where Rd=12∫0T(δxdTQδxd+dTRd)dt+12δxd(T)TPδxd(T). Minimality makes this expression nonnegative for 0<θ≤1; divide by θ and let θ↓0 to get Gu∗[d]≥0. Also Rd≥r2∥d∥22 since Q,P⪰0 and R⪰rI. Taking θ=1 proves J(v)−J(u∗)≥r2∥v−u∗∥22.

1.2givenF3algebra

For the stated sampled objective, subtract the quadrature of ℓw evaluated at the exact state. At every quadrature node, the state-cost difference is bounded by 12∥Q∥∞(2EN+eN)eN; the control-cost summand is unchanged. Nonnegative weights with sum T therefore bound the accumulated state perturbation by T2∥Q∥∞(2EN+eN)eN. The exact-state quadrature discrepancy is at most qN. At T, the terminal quadratic difference is at most 12∥P∥(2MT+eN)eN. Thus ∣JN(w)−J(w)∣≤δN for w=uN,vN with the displayed δN.

2.1givenstep 1.1algebra

The assumed inequalities and consistency give J(uN)≤JN(uN)+δN≤JN(vN)+ηN+δN≤J(vN)+ηN+2δN≤J(u∗)+ρN+ηN+2δN. Subtract J(u∗) and combine with step 1.1 to get the objective-gap bound.

3.1step 1.1step 2.1algebra

Apply the growth inequality of step 1.1 at v=uN. Substitute the upper objective-gap bound from step 2.1, divide by r/2>0, and take nonnegative square roots to obtain the control-error estimate.

4.1A1F1F2F3givenalgebra∎

For any feasible v with ∥v−u∗∥2≤σ, [F2] and [F3] bound the absolute difference of the state running terms by ∥Q∥∞ETCsσ, the terminal terms by ∥P∥MTCsσ, and the control terms by MTMcσ. Hence J(v)−J(u∗)≤CJσ. Under [A1] the cell-average lemma gives strong recovery for the control-only case. If u∗ is Lu-Lipschitz, for each t in a cell its distance from the cell average is at most LuhN, so ∥PNu∗−u∗∥2≤TLuhN. Substitution gives the stated ρN rate and completes the sufficient-estimate branch.

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

38 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources